w2+5w+6=0

Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 6 and whose sum is 5.

2,3

Write the factored form using these integers.

(w+2)(w+3)=0

(w+2)(w+3)=0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

w+2=0

w+3=0

Set the first factor equal to 0.

w+2=0

Subtract 2 from both sides of the equation.

w=-2

w=-2

Set the next factor equal to 0.

w+3=0

Subtract 3 from both sides of the equation.

w=-3

w=-3

The final solution is all the values that make (w+2)(w+3)=0 true.

w=-2,-3

Solve for w w^2+5w+6=0