Solve for y 3(y+4)=-9

$3 (y + 4) = - 9$

Divide each term by $3$ and simplify.

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Divide each term in $3 (y + 4) = - 9$ by $3$ .

$\frac{3 (y + 4)}{3} = \frac{- 9}{3}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 (y + 4)}{3} = \frac{- 9}{3}$

Divide $y + 4$ by $1$ .

$y + 4 = \frac{- 9}{3}$

Divide $- 9$ by $3$ .

$y + 4 = - 3$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $4$ from both sides of the equation.

$y = - 3 - 4$

Subtract $4$ from $- 3$ .

$y = - 7$

Solve for y 3(y+4)=-9

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