Solve for y 5y^2-42y+16=0

Math
5y2-42y+16=0
Factor by grouping.
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For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=5⋅16=80 and whose sum is b=-42.
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Factor -42 out of -42y.
5y2-42y+16=0
Rewrite -42 as -2 plus -40
5y2+(-2-40)y+16=0
Apply the distributive property.
5y2-2y-40y+16=0
5y2-2y-40y+16=0
Factor out the greatest common factor from each group.
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Group the first two terms and the last two terms.
(5y2-2y)-40y+16=0
Factor out the greatest common factor (GCF) from each group.
y(5y-2)-8(5y-2)=0
y(5y-2)-8(5y-2)=0
Factor the polynomial by factoring out the greatest common factor, 5y-2.
(5y-2)(y-8)=0
(5y-2)(y-8)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
5y-2=0
y-8=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
5y-2=0
Add 2 to both sides of the equation.
5y=2
Divide each term by 5 and simplify.
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Divide each term in 5y=2 by 5.
5y5=25
Cancel the common factor of 5.
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Cancel the common factor.
5y5=25
Divide y by 1.
y=25
y=25
y=25
y=25
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
y-8=0
Add 8 to both sides of the equation.
y=8
y=8
The final solution is all the values that make (5y-2)(y-8)=0 true.
y=25,8
The result can be shown in multiple forms.
Exact Form:
y=25,8
Decimal Form:
y=0.4,8
Solve for y 5y^2-42y+16=0

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