Solve for y 7(3)-3y=6

$7 (3) - 3 y = 6$

Multiply $7$ by $3$ .

$21 - 3 y = 6$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $21$ from both sides of the equation.

$- 3 y = 6 - 21$

Subtract $21$ from $6$ .

$- 3 y = - 15$

Divide each term by $- 3$ and simplify.

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Divide each term in $- 3 y = - 15$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 15}{- 3}$

Cancel the common factor of $- 3$ .

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Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 15}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 15}{- 3}$

Divide $- 15$ by $- 3$ .

$y = 5$

Solve for y 7(3)-3y=6

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