Solve for y y+(2y-100)+(y+(2y-100)+1000)=5000

$y + (2 y - 100) + (y + (2 y - 100) + 1000) = 5000$

Simplify $y + 2 y - 100 + y + 2 y - 100 + 1000$ .

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Add $y$ and $2 y$ .

$3 y - 100 + y + 2 y - 100 + 1000 = 5000$

Add $3 y$ and $y$ .

$4 y - 100 + 2 y - 100 + 1000 = 5000$

Add $4 y$ and $2 y$ .

$6 y - 100 - 100 + 1000 = 5000$

Simplify by adding and subtracting.

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Subtract $100$ from $- 100$ .

$6 y - 200 + 1000 = 5000$

Add $- 200$ and $1000$ .

$6 y + 800 = 5000$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $800$ from both sides of the equation.

$6 y = 5000 - 800$

Subtract $800$ from $5000$ .

$6 y = 4200$

Divide each term by $6$ and simplify.

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Divide each term in $6 y = 4200$ by $6$ .

$\frac{6 y}{6} = \frac{4200}{6}$

Cancel the common factor of $6$ .

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Cancel the common factor.

$\frac{6 y}{6} = \frac{4200}{6}$

Divide $y$ by $1$ .

$y = \frac{4200}{6}$

Divide $4200$ by $6$ .

$y = 700$

Solve for y y+(2y-100)+(y+(2y-100)+1000)=5000

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