Solve for z 2(z-4)=3(z-5)

$2 (z - 4) = 3 (z - 5)$

Simplify $2 (z - 4)$ .

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Apply the distributive property.

$2 z + 2 \cdot - 4 = 3 (z - 5)$

Multiply $2$ by $- 4$ .

$2 z - 8 = 3 (z - 5)$

Simplify $3 (z - 5)$ .

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Apply the distributive property.

$2 z - 8 = 3 z + 3 \cdot - 5$

Multiply $3$ by $- 5$ .

$2 z - 8 = 3 z - 15$

Move all terms containing $z$ to the left side of the equation.

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Subtract $3 z$ from both sides of the equation.

$2 z - 8 - 3 z = - 15$

Subtract $3 z$ from $2 z$ .

$- z - 8 = - 15$

Move all terms not containing $z$ to the right side of the equation.

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Add $8$ to both sides of the equation.

$- z = - 15 + 8$

Add $- 15$ and $8$ .

$- z = - 7$

Multiply each term in $- z = - 7$ by $- 1$

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Multiply each term in $- z = - 7$ by $- 1$ .

$(- z) \cdot - 1 = (- 7) \cdot - 1$

Multiply $(- z) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 z = (- 7) \cdot - 1$

Multiply $z$ by $1$ .

$z = (- 7) \cdot - 1$

Multiply $- 7$ by $- 1$ .

$z = 7$

Solve for z 2(z-4)=3(z-5)

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